averaging sublists of different lengths

• To: mathgroup at smc.vnet.net
• Subject: [mg75466] averaging sublists of different lengths
• From: dantimatter <dantimatter at gmail.com>
• Date: Wed, 2 May 2007 03:47:31 -0400 (EDT)

```Hello all,

I have a list of lists like this:

{{70, 66, 64, 68, 64, 56, 68, 78, 62, 68, 84}, {70, 64, 64, 56, 66,
56, 62,
64, 66, 88, 54, 72}, {58, 54, 54, 60, 72, 70, 62, 68, 74, 76, 70},
{66,
56, 60, 64, 56, 62, 68, 58, 58, 58, 68, 76, 62, 76, 66, 64, 88,
56}, {56,
64, 72, 72, 70, 62, 76, 76, 76, 76, 86, 80, 100}, {60, 60, 70, 68,
60, 60,
50, 56, 60, 70, 62, 68, 88, 84, 82}, {54, 66, 72, 62, 70, 66,
70,
56}, {60, 60, 60, 62, 74, 80, 70}, {54, 62, 64, 72, 76, 74}, {66,
74, 70,
80, 54, 54, 64}, {72, 66, 60, 52, 52, 66, 66, 58, 60, 66}}

What I'd really like is the average all the 1st values, 2nd values,
etc, but I'm having trouble figuring out how to deal with the fact
that the lists are not all the same length.   Is there a way to drop
the sublists as they run out of points to add to the average, i.e. if
I want the average of all the nth values, but Length[shortSublist] <
n, can I somehow drop shortSublist and then calculate the average from
the other sublists?

Also, the Mean[] function requires more than one data point, but I'd
still like to extract out the values for which there is only one data
point.  Is there a way to do this?

Thanks!
dan

```

• Prev by Date: A comparison and thanks
• Next by Date: Running a loop for Maximizing problem
• Previous by thread: A comparison and thanks
• Next by thread: Re: averaging sublists of different lengths