Re: Using FindFit with constraints ??
- To: mathgroup at smc.vnet.net
- Subject: [mg75710] Re: [mg75655] Using FindFit with constraints ??
- From: DrMajorBob <drmajorbob at bigfoot.com>
- Date: Wed, 9 May 2007 04:25:23 -0400 (EDT)
- References: <12357150.1178621269861.JavaMail.root@m35>
- Reply-to: drmajorbob at bigfoot.com
I can't read your code -- what the heck is =CF=89? -- but this code
works
just fine in version 6:
model = a Cos[c t];
data = Table[{t, Cos[2.1 t]}, {t, 0, 10, .25}] + RandomReal[.1, 41];
fit = FindFit[data, {model, {a > 0, 1 < c < 2}}, {a, c}, t]
{a -> 0.867956, c -> 2.}
It doesn't work in version 5.2, because (1) RandomReal isn't defined and =
(2) constraints (like {a > 0, 1 < c < 2}) are not supported in the older =
version.
Bobby
On Tue, 08 May 2007 04:45:28 -0500, Alex <axel.kowald at rub.de> wrote:
> Hello everybody,
>
> I saw at http://reference.wolfram.com/mathematica/ref/FindFit.html
> that FindFit can be used with constraints for the parameters. However
> when I try the example with Mathematica 5.2 I get an error.
>
> model = a Cos[=CF=89 t];
> data = Table[{t, Cos[2.1 t]}, {t, 0, 10, .25}] + RandomReal[.1, 41];
> fit = FindFit[data, {model, {a > 0, 1 < =CF=89 < 2}}, {a, =CF==
89}, t]
>
> =>
> FindFit::nlnum: The function value {-1. + Cos[RandomReal[0.1, 41.]] -
> \
> 1=2E\RandomReal[0.1, 41.], \[LeftSkeleton]9\[RightSkeleton], \
> [LeftSkeleton]113\
> \[RightSkeleton]} is not a list of numbers with dimensions {123} at
> {a, =CF=89} = \
> {1, 1}.
>
>
> What am I doing wrong ??
>
> Alex
>
>
>
-- =
DrMajorBob at bigfoot.com