Re: Using FindFit with constraints ??
- To: mathgroup at smc.vnet.net
- Subject: [mg75736] Re: Using FindFit with constraints ??
- From: "Drago Ganic" <dganic at vodatel.net>
- Date: Wed, 9 May 2007 04:39:40 -0400 (EDT)
- References: <f1ph2r$i1q$1@smc.vnet.net>
Hi, well .. as the new documentation says "Updated in 6" it is a new 6.0 feature. You can not use it with 5.2. Upgrade to 6.0! Greetings, Drago "Alex" <axel.kowald at rub.de> wrote in message news:f1ph2r$i1q$1 at smc.vnet.net... > Hello everybody, > > I saw at http://reference.wolfram.com/mathematica/ref/FindFit.html > that FindFit can be used with constraints for the parameters. However > when I try the example with Mathematica 5.2 I get an error. > > model = a Cos[=CF=89 t]; > data = Table[{t, Cos[2.1 t]}, {t, 0, 10, .25}] + RandomReal[.1, 41]; > fit = FindFit[data, {model, {a > 0, 1 < =CF=89 < 2}}, {a, =CF=89}, t] > > => > FindFit::nlnum: The function value {-1. + Cos[RandomReal[0.1, 41.]] - > \ > 1=2E\RandomReal[0.1, 41.], \[LeftSkeleton]9\[RightSkeleton], \ > [LeftSkeleton]113\ > \[RightSkeleton]} is not a list of numbers with dimensions {123} at > {a, =CF=89} = \ > {1, 1}. > > > What am I doing wrong ?? > > Alex > >