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MathGroup Archive 2007

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Re: Using FindFit with constraints ??

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75736] Re: Using FindFit with constraints ??
  • From: "Drago Ganic" <dganic at vodatel.net>
  • Date: Wed, 9 May 2007 04:39:40 -0400 (EDT)
  • References: <f1ph2r$i1q$1@smc.vnet.net>

Hi,
well .. as the new documentation says "Updated in 6" it is a new 6.0 
feature. You can not use it with 5.2. Upgrade to 6.0!

Greetings,
Drago

"Alex" <axel.kowald at rub.de> wrote in message 
news:f1ph2r$i1q$1 at smc.vnet.net...
> Hello everybody,
>
> I saw at http://reference.wolfram.com/mathematica/ref/FindFit.html
> that FindFit can be used with constraints for the parameters. However
> when I try the example with Mathematica 5.2 I get an error.
>
> model = a Cos[=CF=89 t];
> data = Table[{t, Cos[2.1 t]}, {t, 0, 10, .25}] + RandomReal[.1, 41];
> fit = FindFit[data, {model, {a > 0, 1 < =CF=89 < 2}}, {a, =CF=89}, t]
>
> =>
> FindFit::nlnum: The function value {-1. + Cos[RandomReal[0.1, 41.]] -
> \
> 1=2E\RandomReal[0.1, 41.], \[LeftSkeleton]9\[RightSkeleton], \
> [LeftSkeleton]113\
> \[RightSkeleton]} is not a list of numbers with dimensions {123} at
> {a, =CF=89} = \
> {1, 1}.
>
>
> What am I doing wrong ??
>
> Alex
>
> 




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