Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2007
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Working with D, definition of a function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg75995] Re: Working with D, definition of a function
  • From: Szabolcs <szhorvat at gmail.com>
  • Date: Mon, 14 May 2007 03:53:39 -0400 (EDT)
  • Organization: University of Bergen
  • References: <f26nfr$450$1@smc.vnet.net>

Thomas Schmelzer wrote:
> Hi,
> 
> I have defined a map
> 
> ComPath[w_, mu_, bias_] := mu*(\[ImaginaryI]*w + 1)^2 + bias;
> Now, I would like to use the derivative with respect to w as a further 
> function.
> 
> D[ComPath[w, mu, 0], w]
> 
> gives the answer I expect, but
> 
> ComPathPrime[w_, mu_] := D[ComPath[w, mu, 0], w];
> 
> doesn't seem to make sense
> 
> ComPathPrime[2, 1]
> 
> results in
> 
> General::ivar : 2 is  not a valid variable.
> 
> 
> 
> If it seems I have a lack of knowledge about the internals of Mathmatica - 
> that's right.
> 
> Can you briefly explain why this should not work?
> 
> Best,
> 
> Thomas

This is a common mistake new users make. Look up Set and SetDelayed (= 
and :=). You don't need ; at the end of definitions here.

http://reference.wolfram.com/mathematica/tutorial/ImmediateAndDelayedDefinitions.html

You must use
ComPathPrime[w_, mu_] = D[ComPath[w, mu, 0], w]
to get the result you expect.


  • Prev by Date: RE: Mathematica 6.0 - Legend
  • Next by Date: Re: Working with D, definition of a function
  • Previous by thread: Re: Working with D, definition of a function
  • Next by thread: Re: Working with D, definition of a function