Re: Residue Function
- To: mathgroup at smc.vnet.net
- Subject: [mg76087] Re: Residue Function
- From: CKWong <CKWong.P at gmail.com>
- Date: Wed, 16 May 2007 05:24:48 -0400 (EDT)
- References: <email@example.com>
The series expansion only shows that the residue at z=0 is 2. Since equ has only one singularity in the entire complex plane, the residue at infinite is just the negative of that at the singularity, i.e., -2.