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Re: Residue Function

• To: mathgroup at smc.vnet.net
• Subject: [mg76087] Re: Residue Function
• From: CKWong <CKWong.P at gmail.com>
• Date: Wed, 16 May 2007 05:24:48 -0400 (EDT)
• References: <f2bulj$jhe$1@smc.vnet.net>

The series expansion only shows that the residue at z=0 is 2.

Since equ has only one singularity in the entire complex plane, the
residue at infinite is just the negative of that at the singularity,
i.e., -2.