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Re: Residue Function

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  • Subject: [mg76087] Re: Residue Function
  • From: CKWong <CKWong.P at>
  • Date: Wed, 16 May 2007 05:24:48 -0400 (EDT)
  • References: <f2bulj$jhe$>

The series expansion only shows that the residue at z=0 is 2.

Since equ has only one singularity in the entire complex plane, the
residue at infinite is just the negative of that at the singularity,
i.e., -2.

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