Re: Number of Differing Digits & Another Problem (want to

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• Subject: [mg76340] Re: [mg76310] Number of Differing Digits & Another Problem (want to
• From: Bob Hanlon <hanlonr at cox.net>
• Date: Sun, 20 May 2007 02:23:41 -0400 (EDT)

Since you intend to count the bit differences your function needs to be modified to

Clear[BitDifferences];
BitDifferences[a_,b_,n_]:=
n-Count[Equal@@@

t1=Table[BitDifferences[a,b,6],{a,-16,16},{b,-16,16}];

I would use

Clear[BitDifferences];
BitDifferences[a_,b_]:=Module[
{n=Length[IntegerDigits[Max[Abs[{a,b}]],2]]},
n-Count[IntegerDigits[a,2,n]-IntegerDigits[b,2,n],0]];

t2=Table[BitDifferences[a,b],{a,-16,16},{b,-16,16}];

t1==t2

True

Bob Hanlon

---- VenDiddy at gmail.com wrote:
> I just purchased a copy of Mathematica and I've been learning it for
> about a week now. You can expect that I will be posting a lot of
> questions. One thing I've noticed is that there are so many different
> ways to do the same thing!
>
> Here is a function I came up with that calculates how many binary
> digits two numbers differ in:
>
> BitDifferences[a_, b_, n_] :=
>  Count[Equal @@@
>    Thread[{IntegerDigits[a, 2, n], IntegerDigits[b, 2, n]}], True]
>
> For example 5 = 101 differs from 6 = 111 by one digit (the middle
> digit).
>
> I want to see how you would do it so I can broaden my Mathematica
> perspective.
>
> Thanks.
>
>

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