MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Re: What to do in v. 6 in place of

  • To: mathgroup at
  • Subject: [mg76767] Re: [mg76728] Re: What to do in v. 6 in place of
  • From: Bob Hanlon <hanlonr at>
  • Date: Sun, 27 May 2007 04:50:00 -0400 (EDT)
  • Reply-to: hanlonr at

This works for simple cases such as your examples.

   {x_Symbol, xmin_?NumericQ, xmax_?NumericQ},
   opts___] := Module[{d, e, f, y},
   e = Flatten@{expr};
   d = (Denominator@PowerExpand@Log[x, #] & /@ e);
   f = y /. (ToRules@
         Reduce[y^#[[2]] == PowerExpand[#[[1]]^#[[2]]],
          y, Reals] & /@ Thread[{e, d}]);
   Plot[f, {x, xmin, xmax}, opts]];

Grid[{{realPlot[x^(1/3), {x, -8, 8}],
   realPlot[x^(3/5), {x, -8, 8}]},
  {realPlot[{x^(1/3), x^(3/5)}, {x, -8, 8}]}}]

Bob Hanlon

---- Helen Read <read at> wrote: 
> David W.Cantrell wrote:
> > Helen Read <read at> wrote:
> >> Suppose my calculus students want to plot x^(1/3), for say {x,-8,8}. The
> >> problem, of course, is that Mathematica returns complex roots for x<0.
> >> In past versions of Mathematica, we could get the desired real roots
> >> (and plot the function) by loading the package Miscellaneous`RealOnly. I
> >> guess we can still do it that way (and ignore the "obsolete package"
> >> message), but is there a suggested way of doing what we need in 6.0?
> > 
> > Perhaps have them define their own
> > 
> > realCubeRoot[x_]:= Sign[x] Abs[x]^(1/3)
> > 
> > which plots as desired, of course.
> Well, yes, but it's kind of a pain to have to define their own root 
> functions this way on an individual basis. (Not to mention, it 
> completely hoses the derivative. Try realCubeRoot'[x] or 
> realCubeRoot'[-8] and see what you get.)
> I was hoping for a more convenient way to do this in Mathematica 6.0. 
> Surely it *knows* the real nth roots of x for n odd and x<0. It would be 
> nice to be able to define f[x_]=x^(1/3) or x^(3/5) or whatever and just 
> set some option to make it return the real value for x<0.
> --
> Helen Read
> University of Vermont

  • Prev by Date: Quadratic form: symbolic transformation
  • Next by Date: Re: Re: Compatibility woes
  • Previous by thread: Re: Quadratic form: symbolic transformation
  • Next by thread: Re: Re: Re: What to do in v. 6 in place of