Re: Iterate through a list
- To: mathgroup at smc.vnet.net
- Subject: [mg76915] Re: Iterate through a list
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Wed, 30 May 2007 05:13:22 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
- References: <f3gqtq$42r$1@smc.vnet.net>
Nick Hoffman wrote:
> Hello! I'm (somewhat) new to Mathematica and I need help to iterating
> through a list and counting the occurrence of a number.
>
> My list looks like:
>
> {{1,0},{1,1},{2,x+x^2+x^4},{2,1+x+x^2+x^4},{4,x+x^2},{4,1+x+x^2},{4,x+x^4},{4,1+x+x^4},{4,x^2+x^4},{4,1+x^2+x^4},{4,x^3+x^4},{4,1+x^3+x^4},{4,x+x^2+x^3+x^4},{4,1+x+x^2+x^3+x^4},{5,x+x^3},{5,1+x+x^3},{5,x^2+x^3},{5,1+x^2+x^3},{5,x+x^3+x^4},{5,1+x+x^3+x^4},{5,x^2+x^3+x^4},{5,1+x^2+x^3+x^4},{8,x},{8,x^2},{8,x^3},{8,x^4},{8,1+x},{8,1+x^2},{8,1+x^3},{8,x+x^2+x^3},{8,1+x+x^2+x^3},{8,1+x^4}}
>
>
>
> The number that I would need to keep track of is the first in each sub-
> list.
>
> So for the first couple {{1,0},{1,1},{2,x+x^2+x^4},{2,1+x+x^2+x^4},{4,x
> +x^2},........
>
> I would need to keep track of 1,1,2,2,4........
>
> It will not always be 1,2,4,5,8's. The numbers may be completely
> different on each pass. Each sublist may be composed of more items
> but the number that I need to keep track of will always be the 1st in
> the sub-list. Any help or suggestions that you can give me will be
> greatly appreciated. Thanks so much!
>
Part[lst, All, 1] will do what you want.
In[1]:=
lst = {{1, 0}, {1, 1}, {2, x + x^2 + x^4},
{2, 1 + x + x^2 + x^4}, {4, x + x^2},
{4, 1 + x + x^2}, {4, x + x^4}, {4, 1 + x + x^4},
{4, x^2 + x^4}, {4, 1 + x^2 + x^4},
{4, x^3 + x^4}, {4, 1 + x^3 + x^4},
{4, x + x^2 + x^3 + x^4},
{4, 1 + x + x^2 + x^3 + x^4}, {5, x + x^3},
{5, 1 + x + x^3}, {5, x^2 + x^3},
{5, 1 + x^2 + x^3}, {5, x + x^3 + x^4},
{5, 1 + x + x^3 + x^4}, {5, x^2 + x^3 + x^4},
{5, 1 + x^2 + x^3 + x^4}, {8, x}, {8, x^2},
{8, x^3}, {8, x^4}, {8, 1 + x}, {8, 1 + x^2},
{8, 1 + x^3}, {8, x + x^2 + x^3},
{8, 1 + x + x^2 + x^3}, {8, 1 + x^4}};
lst[[All,1]]
Out[2]=
{1, 1, 2, 2, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5,
5, 5, 5, 5, 5, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8}
Regards,
Jean-Marc