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MathGroup Archive 2007

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Re: asymptotics

  • To: mathgroup at smc.vnet.net
  • Subject: [mg76988] Re: asymptotics
  • From: dimitris <dimmechan at yahoo.com>
  • Date: Thu, 31 May 2007 03:25:36 -0400 (EDT)
  • References: <200705241023.GAA21917@smc.vnet.net><f3jib4$doe$1@smc.vnet.net>

m... at inbox.ru       :
> On May 29, 4:05 am, dimitris <dimmec... at yahoo.com> wrote:
> > Thanks a lot for your new response.
> > I think it should be another function (no Series) that do this kind
> > of asymptotic expansions. There are some commands that the other
> > CAS has and I wish Mathematica had (as probably there are various things
> > of Mathematica that a user from the other CAS would want to his system!)
> > but that's life. For example the function identify that appears in a recent
> > question of Daniel Huber I think or the function convert that I really wish
> > Mathematica had something similar.
> >
> > And if, you and Maxim pointed out an asymptotic series like this in
> > the current thread is indeed a simple task for someone to do by the
> > Series command, for something like the following what you would say
> >
> > convert(log(x)*BesselJ(0,x)/sin(x^2),MeijerG);
> > (output is omitted)
> >
> > Dimitris
> >
>
> I would say that convert is a different matter altogether. If you
> really need a conversion to MeijerG, you can try
>
> In[1]:= Integrate`Definite;
>   Integrate`ImproperDump`Mellin[Log[x] BesselJ[0, x]/Sin[x^2], x]
>
> Out[2]= Csc[x^2] Log[x] Integrate`ImproperDump`MeijerGfunction[{}, {},
> {0}, {0}, x^2/4]
>
> This is the output from version 6, and it's essentially the same as
> what is given by the Mysterious Alternate Program (Largely Esteemed).
>
> Maxim Rytin
> m.r at inbox.ru

Now, I really learn something new!
No comments!

Thank you very much!

Dimitris



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