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Re: tetrahedron problem


Hi,

PolyhedronData[""Tetrahedron"] *is* already a 3d graphics and
Show[PolyhedronData["Tetrahedron"]]
but the show is useless because Mathematica will display the
3d graphics without the Show[].

Regards
   Jens

Mark Fisher wrote:
> Hi all,
> 
> PolyhedronData["Tetrahedron"]
> 
> works fine, but
> 
> Show[Graphics3D[PolyhedronData["Tetrahedron"]]]
> 
> generates an error ("Graphics is not a Graphics3D primitive or
> directive.").
> 
> I'm using "6.0 for Microsoft Windows (32-bit) (June 19, 2007)".
> 
> Is this a problem for others? Is this a bug?
> 
> --Mark
> 
> 


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