Re: InverseFourierTransform strange behaviour

*To*: mathgroup at smc.vnet.net*Subject*: [mg82323] Re: InverseFourierTransform strange behaviour*From*: roby.nowak at gmail.com*Date*: Wed, 17 Oct 2007 04:13:05 -0400 (EDT)*References*: <fesjid$ks8$1@smc.vnet.net><ff1qf0$9ao$1@smc.vnet.net>

Hi Frank, sorry but you are not correct. 2 Sqrt[2/Pi] Exp[(w/2)^2] Sin[w]/w is pefectly even (as it is without the negative sign as you suggested) Exp[(w/2)^2] is even Sin[w] is odd 1/w is odd Sin[w]/w is even a simple numerical test too shows that the function is even ( f[x] == f[-x] ) @everybody I am in doubt now if the IFT exists for my function. any suggestions to this ? regards robert On 16 Okt., 09:49, Frank Iannarilli <frank... at cox.net> wrote: > On Oct 14, 4:21 am, roby.no... at gmail.com wrote: > > > In[1]:= 2 Sqrt[2/Pi] Exp[(w/2)^2] Sin[w]/w; > > InverseFourierTransform[%, w, x] > > Your function is actually not even, but I believe you intended it to > be: > 2 Sqrt[2/Pi] Exp[-(w/2)^2] Sin[w]/w > ^^^^ > (note inserted negative sign) > > In this case, everything will work as you expected. > > Regards,