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Re: InverseFourierTransform strange behaviour

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  • Subject: [mg82323] Re: InverseFourierTransform strange behaviour
  • From: roby.nowak at
  • Date: Wed, 17 Oct 2007 04:13:05 -0400 (EDT)
  • References: <fesjid$ks8$><ff1qf0$9ao$>

Hi Frank,

sorry but you are not correct.

2 Sqrt[2/Pi] Exp[(w/2)^2] Sin[w]/w
is pefectly even (as it is without the negative sign as you suggested)

Exp[(w/2)^2]  is even
Sin[w]           is odd
1/w               is odd
Sin[w]/w        is even

a simple numerical test too shows that the function is even ( f[x] ==
f[-x] )


I am in doubt now if the IFT exists for my function. any suggestions
to this ?

regards robert

On 16 Okt., 09:49, Frank Iannarilli <frank... at> wrote:
> On Oct 14, 4:21 am, at wrote:
> > In[1]:= 2 Sqrt[2/Pi] Exp[(w/2)^2] Sin[w]/w;
> > InverseFourierTransform[%, w, x]
> Your function is actually not even, but I believe you intended it to
> be:
>   2 Sqrt[2/Pi] Exp[-(w/2)^2] Sin[w]/w
>                         ^^^^
>                  (note inserted negative sign)
> In this case, everything will work as you expected.
> Regards,

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