wrong answer or no answer?
- To: mathgroup at smc.vnet.net
- Subject: [mg82710] wrong answer or no answer?
- From: Roger Bagula <rlbagula at sbcglobal.net>
- Date: Mon, 29 Oct 2007 05:54:37 -0500 (EST)
M = {{-1, I}, {I, 1}} MatrixPower[M, 1/2] gives {{0, 0}, {0, 0}} So try it as {{a,b},{c,d}} squared: c = b; a = I*Sqrt[1 + b^2]; d = Sqrt[1 - b^2 FullSimplify[{a^2 + b c + 1 == 0, a b + b d - I == 0, a c + c d - I == 0, b c + d^2 - 1 == 0}] {True, -I + b*Sqrt[1 - b^2] +I* b*Sqrt[1 + b^2)]== 0, -I + b*Sqrt[1 - b^2] +I* b*Sqrt[1 + b^2)]== 0, True} Solve[-I + b*Sqrt[1 - b^2] +I* b*Sqrt[1 + b^2)]== 0,b] {} which says there is no solution. This problem comes from the graph of SU(2) and of U(1)*SU(2) as a two vertex 3 directed connections (i,j,k) and a 2 vertex with 4 directed connections (1,i,j,k}. Basically there is either a solution or there is none. Mathematica gives zero and the null set from two different approaches. {{0,i+k},{j,0}} and {{0,i+k},{j+IdentityMatrix[2],0}} It is pretty much a break down of mathematical definitions. The matrix M does appear to have not one, but four solutions the way I do it: M2={{+/-I*Sqrt[1 + b^2], b}, {b, +/-Sqrt[1 + b^2]}} I really may be doing it all wrong. b=+/-Sqrt[+/-1/2+I/2] which gives the stange answers from this code: Clear[b] M2 = {{I*Sqrt[1 + b^2], b}, {b, Sqrt[1 + b^2]}} Det[M2] Solve[Det[M2] == 0, b] b0 = b /. Solve[Det[M2] == 0, b][[2]] M20 = {{-I*Sqrt[1 + b0^2], b0}, {b0, Sqrt[1 + b0^2]}} FullSimplify[M20] FullSimplify[M20.M20] All this leaves me really puzzled. Usually Mathematica takes away my doubts, but here it isn't any help at all. Maybe it is a paradox? Roger Bagula
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