MathGroup Archive 2007

[Date Index] [Thread Index] [Author Index]

Search the Archive

How to invert a function

  • To: mathgroup at
  • Subject: [mg81120] How to invert a function
  • From: Teodoro <jwheeler51 at>
  • Date: Thu, 13 Sep 2007 06:24:59 -0400 (EDT)

this is my first post ro the Mathematica group, so, please be patient ...
The problem I'm trying to solve is a little bit more complex, but
anyway I was able to reproduce the unwanted behaviour using a "toy" example.
As far as I understand the fragment of code

m = 7.984136668700428`*^-14; p = 38.64734299516908`; n =
9.185777`*^-7; q = 7.729468599033817`; r = -9.18579746734159`*^-7;
f[y_] = m Exp[p y];
g[x_] := Solve[f[y] == x, y]
h[x_] := y /. g[x]

allows me to get y as a function of x. To check that h[x] is indeed
the inverse of f[y] (you already know the solution !) one can run


for any value of z you get again z:

z -> h[z] -> f[h[z]=z
z -> f[z] -> h[f[z]=z


Plot[Evaluate[h[x]], {x, 1, 20}, PlotRange -> {Full}]

and get a straight line.
However, when I try to invert

f[y_] = m Exp[p y]+n Exp[q y]+r

I get some result, but the result is WRONG !
In another system I get the correct behaviour, even with more complex
functions ...
I can guess that somewhere in the answers I can get the one I need,
but the Forum is so immense !

  • Prev by Date: Re: help plot log[f[t]] vs a parameter using an ODE
  • Next by Date: Re: LegendreP error (bug?) in Mathematica
  • Previous by thread: Re: Problem with FrameTicks and BarLabels
  • Next by thread: Re: How to invert a function