       Re: Nullcline and getting "2" values for y

• To: mathgroup at smc.vnet.net
• Subject: [mg81482] Re: Nullcline and getting "2" values for y
• From: dh <dh at metrohm.ch>
• Date: Wed, 26 Sep 2007 06:27:54 -0400 (EDT)
• References: <fd7s8h\$cgc\$1@smc.vnet.net>

```
Hello Sean,

I think you are confusing the axes. Your plot shows that there is one

value of fun for every value of y (in the range 0..1), NOT two. However,

there are two values of y for every value of fun.

hope this helps, Daniel

sean_incali wrote:

> I have this equation I can plot using the following

>

> ClearAll["Global`*"]

>

>

> fun = (b c y - a y^ n + y^(1 + n))/(b + y^n);

> d = 0.1;

> c = 1;

> b = 10;

> a = 11;

> n = 5;

> ParametricPlot[{fun, (y)}, {y, 0, 1}, PlotRange -> All]

>

> I am plotting the function "fun" against values of y.

>

> When I do that I get a curvew that clearly shows that, for a given

> value of y, I should get two value for the function.

>

> How do I get what they are?

>

> If I just go..

>

> d = 0.1;

> c = 1;

> b = 10;

> a = 11;

> n = 2;

> y = 0.5;

>

> (b c y - a y^ n + y^(1 + n))/(b + y^n)

>

> I get

>

> 0.231707

>

> but starting at y=0 all the way to y= 0.6 or so, there are two values!

> (according to the graph)

>

> How do I get what those values are?

>

>

> Thanks for any input.

>

> sean

>

>

```

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