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MathGroup Archive 2007

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Re: Nullcline and getting "2" values for y

  • To: mathgroup at smc.vnet.net
  • Subject: [mg81482] Re: Nullcline and getting "2" values for y
  • From: dh <dh at metrohm.ch>
  • Date: Wed, 26 Sep 2007 06:27:54 -0400 (EDT)
  • References: <fd7s8h$cgc$1@smc.vnet.net>


Hello Sean,

I think you are confusing the axes. Your plot shows that there is one 

value of fun for every value of y (in the range 0..1), NOT two. However, 

there are two values of y for every value of fun.

hope this helps, Daniel



sean_incali wrote:

> I have this equation I can plot using the following

> 

> ClearAll["Global`*"]

> 

> 

> fun = (b c y - a y^ n + y^(1 + n))/(b + y^n);

> d = 0.1;

> c = 1;

> b = 10;

> a = 11;

> n = 5;

> ParametricPlot[{fun, (y)}, {y, 0, 1}, PlotRange -> All]

> 

> I am plotting the function "fun" against values of y.

> 

> When I do that I get a curvew that clearly shows that, for a given

> value of y, I should get two value for the function.

> 

> How do I get what they are?

> 

> If I just go..

> 

> d = 0.1;

> c = 1;

> b = 10;

> a = 11;

> n = 2;

> y = 0.5;

> 

> (b c y - a y^ n + y^(1 + n))/(b + y^n)

> 

> I get

> 

> 0.231707

> 

> but starting at y=0 all the way to y= 0.6 or so, there are two values!

> (according to the graph)

> 

> How do I get what those values are?

> 

> 

> Thanks for any input.

> 

> sean

> 

> 




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