Re: making a list using table but with different increment after
- To: mathgroup at smc.vnet.net
- Subject: [mg81538] Re: making a list using table but with different increment after
- From: dh <dh at metrohm.ch>
- Date: Wed, 26 Sep 2007 06:56:54 -0400 (EDT)
- References: <fd7sae$cgl$1@smc.vnet.net>
Hi Sean,
here are some possibilities:
specify the values you want: Table[i,{i,{0,1,2,3,4,5,6,7,8,9,10,20,30}}]
make 2 Lists: Join[Table[i,{i,0,9}],Table[i,{i,10,100,10}]]
make 2 dim. list and flatten: Flatten[ Table[i 10^j,{j,0,1},{i,1,9}] ]
multiply "mantissa" with "exponent": Table[i,{2},{i,1,9}] 10^{0,1}
remember: there is more than one way to do things (like in Perl)
hope this helps, Daniel
sean_incali wrote:
> I can make a list using
>
> Table[a, {a, 0, 100, 10}]
>
> gives
>
> {0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100}
>
>
> But let's say I wanted to make a list that increment in 1 up to 10,
> then increment in 10 onwards.
>
> So that after "tabling" I would get...
>
> {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90,
> 100}
>
> How do I accomplish this?
>
>