Re: Coordinates of vertices
- To: mathgroup at smc.vnet.net
- Subject: [mg87753] Re: [mg87720] Coordinates of vertices
- From: "Maarten van der Burgt" <maarten.vanderburgt at icos.be>
- Date: Wed, 16 Apr 2008 06:51:30 -0400 (EDT)
Peter,
The vertices are in the graphics object.
Just use [[ ]] to get them out.
tc=Truncate[PolyhedronData["Cube"]]
vertices=ph[[1,1]]//N
ListPointPlot3D[vertices ,BoxRatios->Automatic]
Hope this helps,
maarten
"King, Peter R"
<peter.king@imper To: mathgroup at smc.vnet.net
ial.ac.uk> cc:
Subject: [mg87720] Coordinates of vertices
16/04/2008 11:02
I am sure I have done this before but I can't for the life of me
remember how, and I can't find it in the manual. Some help would be much
appreciated. I'd like to find the coordinates of the vertices of a
truncated cube.
Whilst Vertices[cube] correctly gives me the coordinates of a cube
Vertices[Truncate[Polyhedron[Cube]]] doesn't do what I want because
Truncate[Polyhedron[... is a graphics object not a polyhedron object. So
can I convert the graphics object into a polyhedron and use vertices, or
work out the vertices some other way (for a cube this is trivial to do
but for more complicated shapes this is much more tedious)
Thanks,
Peter