Re: ListPlot & lots 'o dots.

*To*: mathgroup at smc.vnet.net*Subject*: [mg87796] Re: [mg87735] ListPlot & lots 'o dots.*From*: "W_Craig Carter" <ccarter at mit.edu>*Date*: Wed, 16 Apr 2008 22:35:40 -0400 (EDT)*References*: <200804160905.FAA24030@smc.vnet.net>

Hello David, I am not sure I understand your question accurately, but if I do understand, then this may be a preferable solution to your problem: (*fresh kernel*) test = Table[{x, Sin[n Pi x]}, {n, 1, 5, 1}, {x, -Pi, Pi, Pi/50}]; (* supply x and y explicitly *) ListPlot[test] ListPlot[test, Joined -> True] ListLinePlot[test] This is a lovely example by the way---I am going to use it as a problem for students to calculate fourier coefficients from data: give 'em the points randomly, extract the coefficients, plot separate curves... Craig Carter On Wed, Apr 16, 2008 at 5:05 AM, Annetts729 <David.Annetts at csiro.au> wrote: > With test data > test = Table[N@Sin[n \[Pi] x], {n, 1, 5, 1}, {x, -\[Pi], \[Pi], \ > [Pi]/50}]; > We can correct the ordinate scale using > > ListPlot[test, Joined->True, DataRange->{-\[Pi], \[Pi]}], and for > lots 'o plots this looks messy. : : > ListPlot[test] (* dotty plot, incorrect ordinate but correct abscissa > & labels -- WTF? *) >

**References**:**ListPlot & lots 'o dots.***From:*Annetts729 <David.Annetts@csiro.au>