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Re: Why isn't Expand[] grouping terms by order?
- To: mathgroup at smc.vnet.net
- Subject: [mg87892] Re: Why isn't Expand[] grouping terms by order?
- From: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>
- Date: Sat, 19 Apr 2008 03:37:03 -0400 (EDT)
- Organization: The Open University, Milton Keynes, UK
- References: <fu9fq7$cbn$1@smc.vnet.net>
p at dirac.org wrote:
> Consider this:
>
> In[19]:= Expand[ (1+a*x)*(1+b*x), x]
>
> 2
> Out[19]= 1 + a x + b x + a b x
>
>
> How can I coax Mathematica to give me this, instead:
>
> 2
> Want[19]= 1 + (a + b) x + a b x
>
> Why isn't Mathematica reporting the answer in terms of powers of x?
The function *Collect[]* is what you are looking for.
In[1]:= Collect[(1 + a*x)*(1 + b*x), x]
Out[1]= 1 + (a + b) x + a b x^2
In[2]:= Expand[(1 + a*x)*(1 + b*x), x]
Out[2]= 1 + a x + b x + a b x^2
In[3]:= Collect[%, x]
Out[3]= 1 + (a + b) x + a b x^2
Regards,
-- Jean-Marc
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