Re: delayed function assignment
- To: mathgroup at smc.vnet.net
- Subject: [mg88190] Re: [mg88170] delayed function assignment
- From: "W_Craig Carter" <ccarter at mit.edu>
- Date: Sun, 27 Apr 2008 07:01:28 -0400 (EDT)
- References: <200804270857.EAA15051@smc.vnet.net>
Hello Leigh, I believe you intended to use patterns in your function definitions: pdf2[x_ ] := ..... cum2[x_ ] = .... instead of pdf2[x] BTW, In most cases, it is better to use 1/4 instead of 0.25. In this case, the results are much more satisfying (to my eye). Best Wishes, Craig 2008/4/27 leigh <leigh.pascoe at gmail.com>: > I am trying to integrate the pdf of a chi-square mixture distribution. > If I define the pdf as > > pdf2[0] := .25 > \!\(pdf2[x] := .5*\(\(1/2\^\(1/ > 2\)\)\/Gamma[1/2]\) \(x\^\(1/2 - 1\)\) \[ExponentialE]\^\(\(-x > \)/ > 2\) + .25*\(1\/\(2*Gamma[1]\)\) \[ExponentialE]\^\(\(-x > \)/2\)\) : : > However if I try to define this as a function of the statistic > obtained, say > > \!\(cum2[x] := 1 - .25 - $B"i(B\_0\%x pdf2[t] \[DifferentialD]t\) > -- W. Craig Carter
- References:
- delayed function assignment
- From: leigh <leigh.pascoe@gmail.com>
- delayed function assignment