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Re: delayed function assignment

• To: mathgroup at smc.vnet.net
• Subject: [mg88201] Re: delayed function assignment
• From: leigh <leigh.pascoe at gmail.com>
• Date: Mon, 28 Apr 2008 04:38:41 -0400 (EDT)
• References: <fv1fec$eru$1@smc.vnet.net>

On Apr 27, 11:02 am, leigh <leigh.pas... at gmail.com> wrote:
> Dear Mathgroup,
>
> I am trying to integrate the pdf of a chi-square mixture distribution.
> If I define the pdf as
>
> pdf2[0] := .25
> \!\(pdf2[x] :=  .5*\(\(1/2\^\(1/
>         2\)\)\/Gamma[1/2]\) \(x\^\(1/2 - 1\)\) \[ExponentialE]\^\(\(-x
> \)/
>               2\) +  .25*\(1\/\(2*Gamma[1]\)\) \[ExponentialE]\^\(\(-x
> \)/2\)\)
>
> I can then obtaing the cumulative distribution function symbolically
> as
>
> In[14]:=\!\($B"i(Bpdf2[x] \[DifferentialD]x\)
>
> Out[14]=\!\(\(-0.25`\)\ 2.718281828459045`\^\(\(-0.5`\)\ x\) + 0.5`\ \
> Erf[0.7071067811865476`\ \@x]\)
>
> I can get numerical values using for example
>
> In[31]:=\!\(1 -  .25 - $B"i(B\_0\%12 pdf2[x] \[DifferentialD]x\)
>
> Out[31]=0.000885691
>
> However if I try to define this as a function of the statistic
> obtained, say
>
> \!\(cum2[x] := 1 -  .25 - $B"i(B\_0\%x pdf2[t] \[DifferentialD]t\)
>
> Then
>
> In[33]:=cum2[9]
>
> Out[33]=cum2[9]
>
> Doesn't evaluate. What should I do to obtain the value as output.
>
> Thanks for your help
>
> Leigh

Oops, I guess it is a while since I have used Mathematica and I
foolishly thought I remembered the correct syntax for a delayed
function assignment. Thank you to those who replied to my post and for
the suggestions.

Leigh