Re: Constructing vector using table

*To*: mathgroup at smc.vnet.net*Subject*: [mg90966] Re: Constructing vector using table*From*: Jean-Marc Gulliet <jeanmarc.gulliet at gmail.com>*Date*: Fri, 1 Aug 2008 02:59:12 -0400 (EDT)*Organization*: The Open University, Milton Keynes, UK*References*: <g6t0i8$3dq$1@smc.vnet.net>

Prateek K Jha wrote: > I am trying to create a vector using "Table" in which I enter a > function that depends on other functions. An excerpt from the code is: > > u2[i_] := 1 + Log[\[CapitalPhi][[i]]]; > un[i_] := > Switch[IntegerPart[i/(m + 1)], 0, u1n[i], 1, u2[i], 2, u2[i]]; > > U = Table[un[i], {i, 1, 3*m}] // MatrixForm; > Dimensions[U] > > Output: > {1} > > Everything runs fine and even the vector is generated when I see the > form of U. But, I am not able to do any operations on this matrix > (like inverse, transpose etc). Even the Dimensions[U] give me 1 while > it should be 60. > > Please help me through if you can. If I am not clear or you need more > info, please let me know MatrixForm[] is a wrapper from printing purpose only. The expression U = Table[un[i], {i, 1, 3*m}] // MatrixForm; is equivalent to U = MatrixForm[Table[un[i], {i, 1, 3*m}]]; What you want is either, U = Table[un[i], {i, 1, 3*m}]; MatrixForm[U] or MatrixForm[U = Table[un[i], {i, 1, 3*m}];] Regards, -- Jean-Marc