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Re: When is a List not a List?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg90977] Re: When is a List not a List?
*From*: Albert Retey <awnl at gmx-topmail.de>
*Date*: Fri, 1 Aug 2008 03:01:21 -0400 (EDT)
*References*: <g6rntk$7kj$1@smc.vnet.net>
Hi,
> g[x_, n_] := x^n
> FullForm[Table[g[x, n], {n, 1, 2}]]
> FullForm[{g[x, 1], g[x, 2]}]
> Plot[{g[x, 1], g[x, 2]}, {x, 0, 1}, PlotStyle -> {Red, Blue}]
> Plot[Table[g[x, n], {n, 1, 2}], {x, 0, 1}, PlotStyle -> {Red, Blue}]
>
> The FullForm[]s are identical.
Plot has Attribute HoldAll, and:
FullForm[Hold[Table[g[x, n], {n, 1, 2}]]]
FullForm[Hold[{g[x, 1], g[x, 2]}]]
are not the same expressions. This means that Plot sees the unevaluated
expressions which are different and so there is no quirk in that it
behaves differently when it sees a list. Of course one could argue that
it could analyze the Table command and find out that that will evaluate
to a two element list, but this is in general not possible without
complete evaluation. E.g.: can you tell how many elements the following
table will have without evaluating it?:
Table[If[RandomReal[]<0.5,x^i,Unevaluated[Sequence[]]],{i,1,10}]
so in these cases it will not try to be smart. If you explicitly tell
Plot to evaluate:
Plot[Evaluate[Table[g[x, n], {n, 1, 2}]], {x, 0, 1}, PlotStyle -> {Red,
Blue}]
or in Version 6 also:
Plot[Table[g[x, n], {n, 1, 2}], {x, 0, 1}, PlotStyle -> {Red, Blue},
Evaluated -> True]
a red and blue curve are shown because now Plot handles identical
expressions (the evaluated ones that you have been looking at).
I think you would find a lot less "bugs" and "quirks" if you would try
to understand the basic mechanisms of how mathematica works. I always
recommend to read the tutorials which are linked here (copy the
following to the adress field within the documentation center):
tutorial/EvaluationOfExpressionsOverview
By reading I mean you definitly should take the time to evaluate the
examples and experiment with them to make sure you get the point.
hth,
albert
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