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Re: Series solution for complicated function


Here are the results with a later version

$Version

6.0 for Mac OS X x86 (64-bit) (February 7, 2008)

expr = MeijerG[{{1}, {3/2}}, {{1, 1}, {0, 1/2}}, x^2]/(4 x^2);

expr2 = FullSimplify[Normal[Series[expr, {x, 0, 2}]]]

-((2*I*Pi*Floor[1/2 - Arg[x]/Pi] + 
         2*Log[x] + 2*EulerGamma - 3)/(2*Pi))

expr4 = FullSimplify[Normal[Series[expr, {x, 0, 4}]]]

(-((19*x^2)/3) + 4*EulerGamma*(x^2 - 6) + 
      4*I*Pi*(x^2 - 6)*Floor[
          1/2 - Arg[x]/Pi] + 4*(x^2 - 6)*
        Log[x] + 36)/(24*Pi)


Bob Hanlon

---- klaus.halterman at gmail.com wrote: 
> I am trying to find the series for MeijerG[{{1}, {3/2}}, {{1, 1}, {0,
> 1/2}}, x^2]/(4 x^2) using my current version of Mathematica 5.0, and
> it fails. Does anyone know the series solution for this up to 2nd
> order, or how I can implement this in my current version of
> Mathematica?
> 
> 
> thanks,
> 
> Klaus.
> 



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