Re: Solving equation and applying solution(s) expression.
- To: mathgroup at smc.vnet.net
- Subject: [mg84551] Re: Solving equation and applying solution(s) expression.
- From: DrMajorBob <drmajorbob at bigfoot.com>
- Date: Thu, 3 Jan 2008 20:27:13 -0500 (EST)
- References: <22010742.1199358196527.JavaMail.root@m08> <op.t4c6rod6qu6oor@monster.gateway.2wire.net>
- Reply-to: drmajorbob at bigfoot.com
Or even better:
3 x/(x^3 + 2) /. Solve[3 x^2 - 2 x + 8 == 0] // ComplexExpand
{-(79/58) - (\[ImaginaryI] Sqrt[23])/
58, -(79/58) + (\[ImaginaryI] Sqrt[23])/58}
Bobby
On Thu, 03 Jan 2008 11:27:14 -0600, DrMajorBob <drmajorbob at bigfoot.com>
wrote:
> 3 x/(x^3 + 2) /. Solve[3 x^2 - 2 x + 8 == 0] // Simplify
>
> {-((27 (\[ImaginaryI] + Sqrt[23]))/(
> 14 \[ImaginaryI] + 20 Sqrt[23])), (27 (-\[ImaginaryI] + Sqrt[23]))/(
> 14 \[ImaginaryI] - 20 Sqrt[23])}
>
> Bobby
>
> On Thu, 03 Jan 2008 04:31:03 -0600, KP <MathematicaUser at gmail.com> wrote:
>
>> Hi Everybody. I am a new subscriber to this group and looking forward
>> to learning from folks who use Mathematica. I have a question and some
>> help will be appreciated.....
>>
>> I want to solve an equation and then apply the solution(s) of the
>> equation to an expression. For example, I want to solve 3 x^2 - 2 x +
>> 8 =0. Then I want to apply the solutions to the expression 3 x / (x^3
>> +2).
>>
>> The equation and the expression above are examples I used to
>> illustrate my question. Please use the equation and the expression to
>> help me out. Thank you and happy new year!
>>
>> --KP
>>
>>
>
>
>
--
DrMajorBob at bigfoot.com