Re: How to ParametricPlot3D a plane given Normal and Distance
- To: mathgroup at smc.vnet.net
- Subject: [mg84686] Re: How to ParametricPlot3D a plane given Normal and Distance
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Thu, 10 Jan 2008 02:22:10 -0500 (EST)
- Organization: Uni Leipzig
- References: <fm22bj$94u$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
Hi,
the implicit version would be
when n={nx,ny,nz}
n.{x,y,z}-d==0
and if you solve this equation for say
z than
{x,y,z /. Solve[n.{x,y,z}-d==0,z][[1]]}
is your parameric form.
Regards
Jens
John Rivers wrote:
> hello
>
> this has eluded me for some reason ...
>
>
> nx = 0; ny = 0; nz = 1; (* plane's surface normal *)
>
> dist = 0; (* distance of plane from origin *)
>
> fx1 = ???;
> fx2 = ???;
> fx3 = ???;
>
> ParametricPlot3D[
> {fx1, fx2, fx3}, (* functions for x y and z coordinates *)
> {t, -10, 10},
> {u, -10, 10}
> ]
>
> what should the functions fx1 fx2 and fx3 be ?
>
> i have been playing around with:
>
> Ax + By + Cz = D
> - and -
> <x, y, z> dot <nx, ny, nz> = D
>
> but not got anywhere yet
>
> thanks
>
> John
>