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Re: Anomaly? or at least a surprise.
*To*: mathgroup at smc.vnet.net
*Subject*: [mg90271] Re: Anomaly? or at least a surprise.
*From*: Szabolcs Horvát <szhorvat at gmail.com>
*Date*: Fri, 4 Jul 2008 03:56:52 -0400 (EDT)
*References*: <g4i942$3cr$1@smc.vnet.net>
Steve Gray wrote:
> Doing D[ArcTan[x], x] gives 1/(x^2+1) as expected.
> Doing Plot[D[ArcTan[x]],{x,-10,10},PlotRange->Full] with no variable
> to differentiate by gives a correct plot (!) This is surprising - Help
> says nothing about leaving out the independent variable even when the
> function is of only one variable.
Note that D[ArcTan[x]] does not evaluate to 1/(x^2+1), but to ArcTan[x].
This is consistent with D[f,x,x] being the double derivative,
D[f,x,x,x] the triple derivative, etc. D[f] is the "zeroth" derivative,
i.e. it does nothing.
> Now, doing
> Plot[D[ArcTan[x], x], {x, -10, 10}, PlotRange -> Full]
> gives error messages such as
>
> General::ivar: -9.18326 is not a valid variable. >>
> General::ivar: -9.59143 is not a valid variable. >>, etc.
>
> I thought that D[ArcTan[x], x] and 1/(x^2+1) should behave identically
> in the Plot statement.
>
> Is this behavior something I should know?
>
Yes, this is related to evaluation order and the Hold* attributes. Plot
has the HoldAll attribtue, i.e. its arguments do not get evaluated
before Plot sees them. So Plot substitutes a number for x in
D[ArcTan[x],x], and not in 1/(x^2+1).
Two solutions:
Plot[Evaluate[D[ArcTan[x], x]], {x, -10, 10}]
or
Plot[D[ArcTan[x],x], {x,-10,10}, Evaluated->True]
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