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Re: Threading over matrices
*To*: mathgroup at smc.vnet.net
*Subject*: [mg90773] Re: [mg90741] Threading over matrices
*From*: Oliver Ruebenkoenig <ruebenko at wolfram.com>
*Date*: Wed, 23 Jul 2008 06:00:17 -0400 (EDT)
*References*: <200807220757.DAA13797@smc.vnet.net>
Hi Robert,
you can make your functions thread over arguments by setting the Listable
attribute.
In[1]:= SetAttributes[myGreater,Listable]
In[2]:= myGreater[x_,y_] := x>y
In[3]:= x = Table[Random[],{3},{4}];
In[4]:= y = Table[Random[],{3},{4}];
In[5]:= a=0.5
Out[5]= 0.5
In[6]:= myGreater[ x, a*y ]
Out[6]= {{True, True, True, True}, {False, True, True, True},
> {True, False, False, True}}
See for example Sin
In[7]:= Attributes[Sin]
Out[7]= {Listable, NumericFunction, Protected}
Hope this helps,
Oliver
On Tue, 22 Jul 2008, Robert <@frank-exchange-of-views.oucs.ox.ac.uk wrote:
> How can I get evaluations to thread over matrices with
> conditional functions?
> Here's examples that show the behaviour that's really
> frustrating me.
> Create a couple of matrices:
>
> x = Table[Random[],{3},{4}];
> y = Table[Random[],{3},{4}];
> a=0.5;
>
> (These are example values I would like the following
> to apply to lists of any dimension.)
> When you add them they create a result with the same
> dimensions where each element corresponds to the
> input elements
>
> x + a y
>
> And some functions do similar
>
> Cos[x] + Sin[a y]
>
> But some don't, e.g.
>
> x > y
> x > a
>
> I would have liked those to produce a matrix of corresponding
> True and False results, and then something like:
>
> If[x > y, 1/x, x - y]
> Piecewise[{{1,x==a},{x^2,x>a}},x y^2]
>
> to produce a matrix of results corresponding to each element.
>
> They don't - I haven't managed to find out why they don't or
> more usefully how to do what I would like them to do.
>
> I have searched Help on all the likely commands (I think: Map,
> Thread, Apply, Distribute, ...) and this archive, where there
> are similar enquiries but none that match. Perhaps I'm looking
> in the wrong place - I expect there's someone who can help.
>
> Robert
>
>
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