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Re: Cos[a x - b] displayed as Cos[b - a x]
*To*: mathgroup at smc.vnet.net
*Subject*: [mg90860] Re: [mg90834] Cos[a x - b] displayed as Cos[b - a x]
*From*: Bob Hanlon <hanlonr at cox.net>
*Date*: Sat, 26 Jul 2008 04:23:47 -0400 (EDT)
*Reply-to*: hanlonr at cox.net
y = HoldForm[Cos[a x - b]]
cos(a x-b)
{y == Cos[a x - b], y == Cos[a x - b] // ReleaseHold}
{cos(a x-b) == cos(b-a x), True}
Bob Hanlon
---- HO JEE HOU <Jeehou.Ho at nottingham.edu.my> wrote:
=============
Dear all,
I have an expression which I wish to put it in the form of Cos[a x - b].
However when I input it to Mathematica, it automatically converted to
Cos[b - a x]. Similarly, for Sin[a x - b] it would become -Sin[b - ax].
I understand that both are equivalent, but I just wish to have the form
of Cos[a x - b]. Is there any way to do this?
Thank you very much.
Best regards,
Ho
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