Re: Cos[a x - b] displayed as Cos[b - a x]

*To*: mathgroup at smc.vnet.net*Subject*: [mg90860] Re: [mg90834] Cos[a x - b] displayed as Cos[b - a x]*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Sat, 26 Jul 2008 04:23:47 -0400 (EDT)*Reply-to*: hanlonr at cox.net

y = HoldForm[Cos[a x - b]] cos(a x-b) {y == Cos[a x - b], y == Cos[a x - b] // ReleaseHold} {cos(a x-b) == cos(b-a x), True} Bob Hanlon ---- HO JEE HOU <Jeehou.Ho at nottingham.edu.my> wrote: ============= Dear all, I have an expression which I wish to put it in the form of Cos[a x - b]. However when I input it to Mathematica, it automatically converted to Cos[b - a x]. Similarly, for Sin[a x - b] it would become -Sin[b - ax]. I understand that both are equivalent, but I just wish to have the form of Cos[a x - b]. Is there any way to do this? Thank you very much. Best regards, Ho