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Re: Log(ln) Function + 2 Parameters + Greater
*To*: mathgroup at smc.vnet.net
*Subject*: [mg89297] Re: Log(ln) Function + 2 Parameters + Greater
*From*: Felipe Mannshardt <vexie.infamous at googlemail.com>
*Date*: Wed, 4 Jun 2008 05:37:27 -0400 (EDT)
*References*: <g22tp5$ikl$1@smc.vnet.net> <g237ef$q4d$1@smc.vnet.net>
dh wrote:
> Hi Felipe,
>
> why are you not simply using an If[] statement:
>
> If[a>0, Plot[...]]
>
> hope this helps, Daniel
>
>
>
> Felipe Mannshardt wrote:
>
>> Hello,
>
>
>> i am having problem telling Mathematica to:
>
>
>> First Try,
>
>
>> Clear[x, f]
>
>> f[x_] := x (a + Log[x])^2
>
>
>> a > 0
>
>> Plot[f[x], {x, -5, 5}]
>
>
>> Second Try,
>
>
>> f[x_] := x (a + Log[x])^2
>
>
>> Plot[f[x], {x, -5, 5}] /.a-> a>0
>
>
>
>> What i want is to tell Mathematica to draw a Graph of f[x] when a>0
>
>
>> Thanks for the help.
>
>
>
>
>
>
Thanks for all replies, worked for my last function, but the suggestions
you guys made so far did work with my last function, but now i have a
new one, and i am here just playing around and i am unable to get it
drawn :(
First to the first Function, i believe the best suggestion was the use
of "if",
But, i can not get it to work :/
Clear[x, f, a]
f[a_][x_] := x (a + Log[x])^2
If[a > 0, Plot[f[x], {x, 0, 2}]]
And all suggestions also did not work at all for my new Function,
f[a_][x_] := (x/E^(ax));
Plot[Table[f[a, x], {a, 0, 2}], {x, 0, 3}]
What am i doing wrong ?
I have already drawn this function by hand,
and i have two types of function,
for a>0 and a<0
But i can not figure out how to draw it in Mathematica :(
Sorry, that i ask so "noob/dumb" questions, but i have already tried
looking in the help and it did not help me further in this problem, so i
believe the best is asking, right ?
Thanks a Lot.
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