       Re: One thing in two ways, with different result.

• To: mathgroup at smc.vnet.net
• Subject: [mg90110] Re: [mg90099] One thing in two ways, with different result.
• From: DrMajorBob <drmajorbob at att.net>
• Date: Sun, 29 Jun 2008 05:35:49 -0400 (EDT)
• References: <27378735.1214649276216.JavaMail.root@m08>

```Compare with

Plot[f[x], {x, -2, 3}, Exclusions -> None]

and I think you'll see what's happening. Plot can "see" the discontinuity
in Piecewise, but not in the other function.

Bobby

On Sat, 28 Jun 2008 04:55:50 -0500, damayi <damayi at gmail.com> wrote:

> Dear all,
> Today I encountered a confused question, and I hope you can help me.
> I defined a function g[x] in the following and Plot it.
> g[x_] := x^3 /; x <= 0
> g[x_] := x /; 0 < x <= 1
> g[x_] := Sin[x] /; x > 1
>
> Then I defined another function f[x] that is the same as g[x] in my
> opinion, and Plot it.
> f[x_] := Piecewise[{{x^3, x <= 0}, {x, 0 < x <= 1}, {Sin[x], x > 1}}]
>
> You will find that Plot[g[x],{x,-2,3}] is different with Plot[f[x],
> {x,-2,3] when x is 1.0
>
> Since g[x] and f[x] are identify, why are these plot different ?
> By the way, my Mathematica is 6.0.2.
>
> Best Regards
> mayi
> 2008-6-27
>
>

--
DrMajorBob at longhorns.com

```

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