Re: One thing in two ways, with different result.
- To: mathgroup at smc.vnet.net
- Subject: [mg90116] Re: One thing in two ways, with different result.
- From: "David Park" <djmpark at comcast.net>
- Date: Sun, 29 Jun 2008 05:36:56 -0400 (EDT)
- References: <g451vv$pqg$1@smc.vnet.net>
A nice example!
This is the advantage of using Piecewise over multiple conditional
definitions. With Piecewise Mathematica can find the breakpoints provided
simple intervals are given. But not with multiple conditional definitions.
It then excludes the breakpoints. But you could specify the breakpoints by
using the Exclusions option.
g[x_] := x^3 /; x <= 0
g[x_] := x /; 0 < x <= 1
g[x_] := Sin[x] /; x > 1
f[x_] := Piecewise[{{x^3, x <= 0}, {x, 0 < x <= 1}, {Sin[x], x > 1}}]
Plot[f[x], {x, -2, 3}]
Plot[g[x], {x, -2, 3}]
Plot[g[x], {x, -2, 3}, Exclusions -> {0, 1}]
Piecewise seems to work even if we try to disguise where the breakpoints
are. Probably because Mathematica u uses Reduce on the conditions before
plotting.
h[x_] := Piecewise[{{x^3, x <= 0}, {x,
0 < x^2 <= 4 \[And] x > 0}, {Sin[x], x^2 > 4 \[And] x > 0}}]
Plot[h[x], {x, -2, 5}]
--
David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/
"damayi" <damayi at gmail.com> wrote in message
news:g451vv$pqg$1 at smc.vnet.net...
> Dear all,
> Today I encountered a confused question, and I hope you can help me.
> I defined a function g[x] in the following and Plot it.
> g[x_] := x^3 /; x <= 0
> g[x_] := x /; 0 < x <= 1
> g[x_] := Sin[x] /; x > 1
>
> Then I defined another function f[x] that is the same as g[x] in my
> opinion, and Plot it.
> f[x_] := Piecewise[{{x^3, x <= 0}, {x, 0 < x <= 1}, {Sin[x], x > 1}}]
>
> You will find that Plot[g[x],{x,-2,3}] is different with Plot[f[x],
> {x,-2,3] when x is 1.0
>
> Since g[x] and f[x] are identify, why are these plot different ?
> By the way, my Mathematica is 6.0.2.
>
> Best Regards
> mayi
> 2008-6-27
>