Re: I couldn't solve a pde problem with boundary values in mathematica
- To: mathgroup at smc.vnet.net
- Subject: [mg86139] Re: I couldn't solve a pde problem with boundary values in mathematica
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Mon, 3 Mar 2008 04:40:20 -0500 (EST)
- References: <fqetau$jhc$1@smc.vnet.net>
Hi,
> t(-h/2,Z)=0
> t(h/2,Z)=0
are only two points and not the boundary.
And if you mean
t(-h/2,z)=0
t(h/2,z)=0
the boundary conditions are inconsistent with
t(y,0)=\sigma
and no solution exist in this case.
Regards
Jens
PS: Can you use Mathematica syntax
atepe wrote:
> Hi,
>
> I am trying to solve the following partial differential equation with 4 boundary conditions with mathematica. But it doesn't work.
>
> sigma is a constant in here.
> ****************************
> Simplify[DSolve[
> t[y, z] - \[Gamma]^2*(D[t[y, z], {y, 2}] +
> D[t[y, z], {z, 2}]) == \[Sigma], t, {y, z}]]
>
> The boundary conditions are:
> t(y,0)=\sigma
> t(y,L)=\sigma
> t(-h/2,Z)=0
> t(h/2,Z)=0
>
> Does anyone know how to solve the problem?
>
> Thanks for advance
>