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Re: Methods for plotting
- To: mathgroup at smc.vnet.net
- Subject: [mg86309] Re: Methods for plotting
- From: "Steve Luttrell" <steve at _removemefirst_luttrell.org.uk>
- Date: Sat, 8 Mar 2008 05:40:40 -0500 (EST)
- References: <fqqs4b$kgg$1@smc.vnet.net>
Your expression is not written in Mathematica. I assume the left hand side
of your equation is meant to be
lhs=Exp[-x]/((x^2 + 1) (y^2 + 2) (z^2 + 1)) +
Exp[-2 y]/((x^2 + 2) (y^2 + 2) (z^2 + 1)) +
Exp[-3 z]/((x^2 + 1) (y^2 + 2) (z^2 + 3))
Assuming x,y,z are all real-valued, then each of the 3 terms in this
expression is positive, so lhs can never be zero, so there is no contour
surface lhs==0 for you to plot. An exception is when x,y,z all tend to
+Infinity which makes lhs-->0.
Stephen Luttrell
West Malvern, UK
"Paolo" <paolomarracino at hotmail.com> wrote in message
news:fqqs4b$kgg$1 at smc.vnet.net...
> Hi, I'm new in this forum and I hope you'll help me to solve a little
> problem with Mathematica(5.0), that I just started to use. I have an
> equation (coming from the divergence of a vector) and it's form is similar
> to:
> [exp(-x)]/[(x^2+1)(y^2+2)(z^2+1)]+
> [exp(-2y)]/[(x^2+2)(y^2+2)(z^2+1)]+
> [exp(-3z)/[(x^2+1)(y^2+2)(z^2+3)]=0
>
> I have difficulties to plot this implicit function, i used Plot3d and
> ImplicitPlot with no success and the error message that I get involves the
> non-algebraic way the programm uses to solve the equation.
> Is there any other Plot-type function that can possibly solve this
> problem?
>
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