Re: Puzzled by the "Variance"

• To: mathgroup at smc.vnet.net
• Subject: [mg86533] Re: Puzzled by the "Variance"
• From: giovanni resta <g.restaCUT at CUTiit.cnr.it>
• Date: Thu, 13 Mar 2008 04:32:31 -0500 (EST)
• References: <fr8b97\$h2s\$1@smc.vnet.net>

```Elements wrote:
> Greeting all
> I'm puzzled by the function "Variance". We can learn how to calculate
> For example, calculate the sample variance of {1,2,3}. the average of
> {1,2,3} is 2, then the variance should be ((1-2)^2+(2-2)^2+(3-2)^2)/3=2/3.
> But mathematica gives that:
>
> In[10]:= Variance[{1.0,2.0,3.0}]
> Out[10]= 1.
>
> Why??

Because, as it is explained in the help page, Variance[list] is computed as
Total[(list-Mean[list])^2]/(Length[list]-1)

So the total is divided by (number of elements)-1 and not by (no. of elements).

g.

```

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