       Re: How to programmatically rewrite (x + y/z) as (xz+ y)/z ?

• To: mathgroup at smc.vnet.net
• Subject: [mg89183] Re: How to programmatically rewrite (x + y/z) as (xz+ y)/z ?
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Wed, 28 May 2008 04:46:38 -0400 (EDT)
• Organization: Uni Leipzig
• References: <g1gqk6\$1g1\$1@smc.vnet.net>
• Reply-to: kuska at informatik.uni-leipzig.de

```Hi
(x + y/z) // Together

??

Regards
Jens

TuesdayShopping wrote:
> Given "(x + y/z)" as input, how do I get the same expression in the form of "(xz+ y)/z".
>
> Note that the input form may not always have 2 terms. It may be arbitrarily long or may not be in any standard form. It may be like  "x+y", or "x + y + (2*w)/z - p/3 +10", or "c", or  "x/2"   . . . .All that can be assumed about the input is that they are all polynomials bound together with the 5 operators (+, -, *, / and ^), and that whatever the output is, the denominator can be assumed to be not equal to 0.
>
> Thanks a lot.
>

```

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