Re: simplify polynomial

• To: mathgroup at smc.vnet.net
• Subject: [mg89210] Re: [mg89186] simplify polynomial
• From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
• Date: Thu, 29 May 2008 07:05:22 -0400 (EDT)
• References: <200805280847.EAA27235@smc.vnet.net>

```On 28 May 2008, at 17:47, vmarian wrote:

> I want to simplify a polynomial by factorizing the most of the
> terms as possible(that means a product of terms plus a small other
> number of terms). I didn't find how to do such incomplete
> factorization. Is there a command to do it. Factor works only for
> complete factorizations.
>
> \!\(Simplify[2 - =CE=BB - =CE=BB\^2 - 3\ hmb\ \((\(-2\) + =CE=BB +
>      =CE=BB\^2)\) + hmb\^3\ \((5 - 12\ =CE=BB + 4\ =CE=BB\^2)\) + hmb\^2\ \((6 -
> 3\ =CE=BB -
>      8\ =CE=BB\^2 + 2\ =CE=BB\^3)\)]\)
>
> Thank you.
>

You have to define uniquely the "factorization" that want. There is
nothing in what you write that suggests any kind of unique definition.
And if you can't define it in a unique way, you should at least give
some criterion which determines what makes a good "factorization" and
what does not. For example:
(x - 1)*(x - 2) - 1  is always equal to (x - 4)* (x + 1) + 5. So which
of these is a better "incomplete factorization" and why? Unless you
can provide such information your question does not make sense.

Andrzej Kozlowski

```

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