Re: Trinomial decics x^10+ax+b = 0; Help with Mathematica code
- To: mathgroup at smc.vnet.net
- Subject: [mg93298] Re: [mg93280] Trinomial decics x^10+ax+b = 0; Help with Mathematica code
- From: "Tito Piezas" <tpiezas at gmail.com>
- Date: Mon, 3 Nov 2008 05:26:27 -0500 (EST)
- References: <200811020657.BAA02645@smc.vnet.net>
Hello Bob, There is no non-trivial solution with {a,|b|} < 100? That is strange. There are an *infinite* number of solutions such that an irreducible x^6+ax+b or x^8+ax+b factors over a Sqrt[] extension. A non-trivial soln {a,b} such that the 45-deg resultant has a 10th deg (or 5th deg) factor would mean that x^10+ax+b factors over a Sqrt (or a quintic) extension. I will extend the range to {a,|b|} < 1000 tomorrow when I have time. Lots of thanks. :-) Tito On Sun, Nov 2, 2008 at 12:45 PM, Bob Hanlon <hanlonr at cox.net> wrote: > eqns = {-a + m^9 - 8 m^7 n + 21 m^5 n^2 - 20 m^3 n^3 + 5 m n^4 == 0, > -b + m^8 n - 7 m^6 n^2 + 15 m^4 n^3 - 10 m^2 n^4 + n^5 == 0}; > > R[m_, a_, b_] = Resultant[Sequence @@ First /@ eqns, n] > > m^45+246 a m^36-502 b m^35-13606 a^2 m^27+51954 a b m^26-73749 b^2 m^25-245 > \ > a^3 m^18+135060 a^2 b m^17-92850 a b^2 m^16+383750 b^3 m^15+13605 a^4 \ > m^9+27200 a^3 b m^8+25125 a^2 b^2 m^7+12500 a b^3 m^6+3125 b^4 m^5-a^5 > > For a = 0 and b != 0 there will always be a quintic factor > > {R[m, 0, 0], R[m, 0, b]} // Factor > > {m^45,m^5 (m^20-625 b m^10+3125 b^2) (m^20+123 b m^10+b^2)} > > To test factored polynomials for factors of a specific degree > > Clear[FactorQ]; > > FactorQ[factoredPoly_Times, deg_Integer, m_Symbol] := > > Or @@ (FactorQ[#, deg, m] & /@ (List @@ factoredPoly)); > > FactorQ[factoredPoly_Power, deg_Integer, m_Symbol] := > > If[factoredPoly === m^deg, True, FactorQ[factoredPoly[[1]], deg, m]]; > > FactorQ[factoredPoly_, deg_Integer, > m_Symbol] := > (Length[CoefficientList[factoredPoly, m]] - 1) == deg; > > FactorQ[#, 2, x] & /@ > {(x + 1) (x + 2), (x + 1)^2 (x + 2), x^2, (x + 1)^2, > x^2 + 1, (x^2 + 1) (x + 2), (x^2 + 1)^3 (x + 2)} > > {False,False,True,False,True,True,True} > > polys1 = Flatten[ > Table[{a, b, Factor[R[m, a, b]]}, {a, -100, -1}, {b, -100, 100}], 1]; > > ans1 = Select[polys1, FactorQ[#[[3]], 5, m] || FactorQ[#[[3]], 10, m] &] > > {} > > polys2 = Flatten[ > Table[{a, b, Factor[R[m, a, b]]}, {a, 1, 100}, {b, -100, 100}], 1]; > > ans2 = Select[polys2, FactorQ[#[[3]], 5, m] || FactorQ[#[[3]], 10, m] &] > > {} > > Not too encouraging for finding other cases. > > > Bob Hanlon > > ---- tpiezas at gmail.com wrote: > > ============= > Hello guys, > > I need some help with Mathematica code. > > It is easy to eliminate "n" between the two eqn: > > -a + m^9 - 8m^7n + 21m^5n^2 - 20m^3n^3 + 5mn^4 = 0 > -b + m^8n - 7m^6n^2 + 15m^4n^3 - 10m^2n^4 + n^5 = 0 > > using the Resultant[] command to find the rather simple 45-deg > polynomial in "m", call it R(m). > > As Mathematica runs through integral values of {a,b}, if for some > {a,b} the poly R(m) factors, we are interested in two cases: > > Case1: an irreducible decic factor > Case2: an irreducible quintic factor > > What is the Mathematica code that tells us what {a,b} gives Case 1 or > Case 2? > > > Thanks. :-) > > > Tito > > > > > -- > > Bob Hanlon > >
- References:
- Trinomial decics x^10+ax+b = 0; Help with Mathematica code
- From: tpiezas@gmail.com
- Trinomial decics x^10+ax+b = 0; Help with Mathematica code