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Re: NIntegrate[UnitStep[...]PDF[...],{x,...}] hard to integrate

On Nov 6, 4:07 am, Bill Rowe <readn... at> wrote:
> On 11/5/08 at 4:57 AM, erwann.rog... at (er) wrote:
> >f[x_]=(0.014999775454701741*E^(5.264*x) +
> >E^(2.632*x)*(-0.012692488700608462 - 0.14964297032258167*x))/
> >(12.579644604014753 + 7.102251209677398*E^(2.632*x) + E^(5.264*x))
> >g[t_]:=NIntegrate[ UnitStep[t-f[x]] PDF[
> >NormalDistribution[0,1/2],x], {x,-Infinity,Infinity} ]
> >g[0] runs for a very long time before forcing the kernel to quit,
> >let alone FindRoot[g[t]==0.25,{t,-1,1}]
> >Note that f[x]PDF[NormalDistribution[0,1/2],x] integrates to 0 and i
> >virtually zero outside [-2,2]
> >I use Mathematica 5.2/Ubuntu/4GB/IntelCoreDuo2
> >any recommandation?
> I wonder if you have defined g as you intended.
> A plot of f[x] shows it everywhere positive except the interval
> from 0 to ~.8. This can be refined by doing
> In[8]:= FindRoot[f[x], {x, .8}]
> Out[8]= {x->0.84719}
> So, UnitStep[t-f[x]] will be 0 outside this interval when t = 0.
> This means g[0] amounts to integrating the PDF of a normal
> distribution from 0 to .84719. For any distribution the integral
> of the PDF is the CDF. The median of NormalDistribution[0,a] is
> 0. So, g[0] must be
> In[10]:= CDF[NormalDistribution[0, 1/2], .84719] - .5
> Out[10]= 0.454903
> The way you have set the problem up, you are asking Mathematica
> to do a lot more work than is needed to solve the problem.

Thank you.

What was said above would suffice if I were only concerned with a
small finite subsets of values of t. The larger problem, however, as I
hinted in the first post, is FindRoot[g[t]==0.25,{t,-1,1}].  If
Mathematica cannot compute g[t], I can forget about FindRoot
altogether. I hope not, and that someone has a better grasp of
Mathematica than I have who can help.

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