Re: right hand side

*To*: mathgroup at smc.vnet.net*Subject*: [mg93568] Re: [mg93530] right hand side*From*: Bob Hanlon <hanlonr at cox.net>*Date*: Sat, 15 Nov 2008 06:02:24 -0500 (EST)*Reply-to*: hanlonr at cox.net

aa = 2*x + 5*y == 1; y /. Solve[aa, y][[1]] (1/5)*(1 - 2*x) Last[Reduce[aa, y]] // Simplify (1/5)*(1 - 2*x) An alternate way to extract the results of Reduce y /. ToRules[Reduce[aa, y]] // Simplify (1/5)*(1 - 2*x) Bob Hanlon ---- magdamoczydlowska at gmail.com wrote: ============= Hello Everyone! I suppose that my question can be very easy. I will translate it on simple equation, aa = 2*x + 5*y == 1, I need to plot this equation so i take Reduce [aa,y], the result is following y == 1/5 - (2 x)/5. Now I would like to take right side of equation to plot 1/5-(2x)/5. However I do not know how to do it. Thank you for help, Magdalena -- Bob Hanlon