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Re: Reduce[a^x + b^x - 2 == 0, x]


It seems the equation is not solvable in an algebraic way. However, I
give you one solution: x=0. Depending on a and b there may be one
other solution.

You should probably try to solve this numerically.

Cheers -- Sjoerd

On Nov 19, 12:39 pm, "Severin Posta" <seve... at km1.fjfi.cvut.cz> wrote:
> If I put
>
> Reduce[a^x + b^x - 2 == 0, x]
>
> into Mathematica 6.0.0 Win32, I get no result. System is running computat=
ion
> several days - probably forever :)
>
> S.



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