Re: Expressing values in the legend in terms of original data

*To*: mathgroup at smc.vnet.net*Subject*: [mg92514] Re: Expressing values in the legend in terms of original data*From*: er <erwann.rogard at gmail.com>*Date*: Thu, 2 Oct 2008 04:36:25 -0400 (EDT)*References*: <gbvlva$bdf$1@smc.vnet.net> <gc0tm2$9ef$1@smc.vnet.net>

On Oct 1, 6:30 pm, Jens-Peer Kuska <ku... at informatik.uni-leipzig.de> wrote: > Hi, > > the legend here is complete right, try > Plot3D[2 Sin[x y], {x, -\[Pi]/2, \[Pi]/2}, {y, -\[Pi]/2, \[Pi]/2}] > > and so, simply remove the 2 > > Plot3D[Sin[x y], {x, -\[Pi]/2, \[Pi]/2}, {y, -\[Pi]/2, \[Pi]/2}] > > and the problem is fixed. > > Regards > Jens > > er wrote: > > Hi, > > > Considering > > > contourPlotFun= > > ContourPlot[2 Sin[x y],{x,-\[Pi]/2,\[Pi]/2},{y,-\[Pi]/2,\[Pi]/2= }, > > DisplayFunction\[Rule]Identity]; > > > ShowLegend[ > > contourPlotFun,{GrayLevel[1-#]&,10," 1","-1", > > LegendPosition\[Rule]{1.1,-.4}}]; > > > The legend here is misleading, because the min and max values are -2 > > and 2, respectively, not -1 and 1. So how can I modify the input to > > ShowLegend to reflect that? > > > Thanks! Thanks, but perhaps I did not make myself clear. I chose 2 Sin[x y] precisely because the range is [-2,2]. I'm not trying to fit the data to the legend, but rather the legend to the data.