Re: Expressing values in the legend in terms of original data

*To*: mathgroup at smc.vnet.net*Subject*: [mg92572] Re: Expressing values in the legend in terms of original data*From*: "sjoerd.c.devries at gmail.com" <sjoerd.c.devries at gmail.com>*Date*: Mon, 6 Oct 2008 04:13:42 -0400 (EDT)*References*: <gbvlva$bdf$1@smc.vnet.net>

Er, In my version of Mathematica (6.03 WinXP) the ContourPlot is in color by default. It doesn't make sense to add a grayscale legend. So either you color the legend or you add a greyscale ColorFunction to the ContourPlot: contourPlotFun = ContourPlot[ 2 Sin[x y], {x, -\[Pi]/2, \[Pi]/2}, {y, -\[Pi]/2, \[Pi]/2}, ColorFunction -> (GrayLevel[1 - #] &)]; ShowLegend[contourPlotFun, {GrayLevel[1 - #] &, 10, " 2", "-2", LegendPosition -> {1.1, -.4}}] The legend doesn't adapt to the range of your plot. You have to provide the range yourself. In the expression above I put in 2 and -2 and that does the trick. Cheers, Sjoerd On Oct 1, 1:12 pm, er <erwann.rog... at gmail.com> wrote: > Hi, > > Considering > > contourPlotFun= > ContourPlot[2 Sin[x y],{x,-\[Pi]/2,\[Pi]/2},{y,-\[Pi]/2,\[Pi]/2}, > DisplayFunction\[Rule]Identity]; > > ShowLegend[ > contourPlotFun,{GrayLevel[1-#]&,10," 1","-1", > LegendPosition\[Rule]{1.1,-.4}}]; > > The legend here is misleading, because the min and max values are -2 > and 2, respectively, not -1 and 1. So how can I modify the input to > ShowLegend to reflect that? > > Thanks!