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Re: How to print TraditionalForm without evaluation
*To*: mathgroup at smc.vnet.net
*Subject*: [mg92641] Re: How to print TraditionalForm without evaluation
*From*: David Bailey <dave at Remove_Thisdbailey.co.uk>
*Date*: Thu, 9 Oct 2008 06:36:21 -0400 (EDT)
*References*: <gci1sm$iv$1@smc.vnet.net>
Serych Jakub wrote:
> I want to write notebook which prints simple integration examples with
> results for the students.
> Something like:
>
> ex1 = (1 - 3*x^3 + 2*x^5)/(4*x^3);
> ex2 = (-5*x^(1/4) + (x^2)^(4/3))/x^(3/2);
>
> Grid[{
> Table[
> TraditionalForm[Integrate[Symbol["ex" <> ToString[nr]], x]], {nr, 1, 2}],
> (* do not integrate this *)
> Table[
> TraditionalForm[Integrate[Symbol["ex" <> ToString[nr]], x]], {nr, 1, 2}]},
> (* integrate this *)
> Frame -> All, ItemStyle -> Directive[FontSize -> 18, Bold]]
>
> (there will be much more examples ex3,ex4, etc.)
>
> This works nice, but I need to tell Mathematica not to Integrate in the first
> row of the table - examples (only in the second one - results). Is there any
> possibility to suppress the evaluation of the Integral in the first row of
> the grid and just print the symbol of Integral and the TraditionalForm of the
> example behind it?
>
> May be this is a newbie kind of question, but I have spent lot of time on it,
> and I cannot solve it.
>
> Thanks in advance for any help
>
> Jakub
>
HoldForm prevents evaluation, but your requirements are slightly more
complicated because you do need to obtain the value of ex1, etc. I
expect you have already encountered that gotcha! Here is some code that
works, and also eliminates the clumsiness of constructing symbols just
in order to access a list of things:
ex[1] = (1 - 3*x^3 + 2*x^5)/(4*x^3);
ex[2] = (-5*x^(1/4) + (x^2)^(4/3))/x^(3/2);
Grid[{Table[
TraditionalForm[
With[{exx = ex[nr]}, HoldForm[Integrate[exx, x]]]], {nr, 1,
2}],(*do not integrate this*)
Table[TraditionalForm[
Integrate[Symbol["ex" <> ToString[nr]], x]], {nr, 1,
2}]},(*integrate this*)Frame -> All,
ItemStyle -> Directive[FontSize -> 18, Bold]]
Notice that the 'With' construct injects the value of ex[nr] inside the
HoldForm construction, but the HoldForm still prevents further
evaluation - which is exactly what you want.
David Bailey
http://www.dbaileyconsultancy.co.uk
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