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Re: Newbie question: equations with sums.


(Sum[i*f[i], {i, 0, -1 + n}] /. i -> k) == 
    Sum[k*f[k], {k, 0, -1 + n}]

True


Bob Hanlon

---- Vend <vend82 at virgilio.it> wrote: 

=============
Hello.

FullSimplify[\!\(
\*UnderoverscriptBox[\(\[Sum]\), \(i = 0\), \(\(-1\) + n\)]i\ f[
     i]\) == \!\(
\*UnderoverscriptBox[\(\[Sum]\), \(k = 0\), \(\(-1\) + n\)]k\ f[k]\)]

Evaluates to:

\!\(
\*UnderoverscriptBox[\(\[Sum]\), \(i = 0\), \(\(-1\) + n\)]i\ f[
    i]\) == \!\(
\*UnderoverscriptBox[\(\[Sum]\), \(k = 0\), \(\(-1\) + n\)]k\ f[k]\)

Why doesn't it evaluate to true? Is there a way to make the system
solve this kind of equations?


--

Bob Hanlon



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