Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2008

[Date Index] [Thread Index] [Author Index]

Search the Archive

Good computer needed

  • To: mathgroup at smc.vnet.net
  • Subject: [mg93014] Good computer needed
  • From: Artur <grafix at csl.pl>
  • Date: Fri, 24 Oct 2008 02:27:10 -0400 (EDT)
  • References: <gdkajv$4r2$1@smc.vnet.net> <200810220941.FAA00792@smc.vnet.net>
  • Reply-to: grafix at csl.pl

Dear Friends,
I would like to ask person which have access to quick computer with big 
memory with installed Mathematica to run bellow procedure (I was stop my 
old PC computer after 7 days of run this proceduer, Mathematica was used 
Hard Drive because memory was not sufficient). I hope that strong 
machine count these few hours.
I will be greatfull for help because I don't have access to any better 
computer as myself.
Best wishes
Artur

NSolve[{(3 c^2 d + 3 b d^2 + 6 b c e + 3 d e^2 + e^3 + 3 b^2 f +
     3 d^2 f + 6 c e f + 6 d e f + 3 b f^2 + 3 c f^2 +
     f^3) == -960 I Sqrt[3/
    2869], (c^3 + 6 b c d + 3 b^2 e + 3 d^2 e + 3 c e^2 + 3 d e^2 +
     6 c d f + 3 d^2 f + 6 b e f + 6 c e f + 3 b f^2 + 3 e f^2 +
     2 f^3) ==
   1200 I Sqrt[3/
    2869], (20 - 1500 I Sqrt[3/2869]) == (3 b c^2 + 3 b^2 d + d^3 +
     6 c d e + 3 d^2 e + 3 b e^2 + 3 c e^2 + 3 c^2 f + 6 b d f +
     6 c d f + 6 b e f + 3 e^2 f + 3 d f^2 + 6 e f^2 +
     f^3), (3 b^2 c + 3 c d^2 + d^3 + 3 c^2 e + 6 b d e + 6 c d e +
     3 b e^2 + e^3 + 6 b c f + 3 c^2 f + 6 b d f + 6 d e f +
     6 e^2 f + 3 c f^2 + 6 d f^2 + 3 e f^2) == (-25 +
     1875 I Sqrt[3/2869]) ,
  b^3 + 3 c d^2 + 3 c^2 e + 6 b d e + e^3 + 6 b c f + 6 d e f +
    3 e^2 f + 3 c f^2 + 3 d f^2 == 768 I Sqrt[3/2869]}, {b, c, d, e,
  f}, WorkingPrecision -> 2000]//Timing



  • Prev by Date: How does Mathematica know whether a number is real or complex?
  • Next by Date: Re: How does Mathematica know whether a number is real or complex?
  • Previous by thread: Re: Is there a simple way to transform 1.1 to 11/10?
  • Next by thread: Re: Re: Is there a simple way to transform 1.1 to 11/10?