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Re: Controlling the order of evaluations
*To*: mathgroup at smc.vnet.net
*Subject*: [mg93051] Re: [mg92985] Controlling the order of evaluations
*From*: Bob Hanlon <hanlonr at cox.net>
*Date*: Fri, 24 Oct 2008 02:34:15 -0400 (EDT)
*Reply-to*: hanlonr at cox.net
f[x_?NumericQ, y_?NumericQ] :=
NIntegrate[2^(s*x), {s, 0, y}]
Plot[f[x, #] & /@ {2, 3, 4, 5}, {x, 0.5, 1.5}]
Bob Hanlon
---- anguzman at ing.uchile.cl wrote:
=============
Hello:
Several times I have faced similar problems to this one:
Suppose I have a function f[x,y] well defined only in numbers, I mean,
it drops errors if I try to evaluate symbols. You could suppose that
is a function that include numerical integration in its definition...
What I want to do is plotting several curves f[x,y1], f[x,y2],...f[x,yn]
with x as abscissa for specific (and fixed) values of y in the same plot.
So, what I always end up trying is something like:
Plot[f[x,#]&/@{y1,y2,....,yn},{x,a,b}]
Mathematica (5.2 Version for Windows) complains but finally interprets
correctly what I meant and does the plot correctly (sometimes)with all
the curves , but this errors are annoying. They are always of the form:
\" bla bla.. f[x,y1] is not numerical at ....\"
I would be very gratefull if somebody could explain me (or just give
the solution to this thing) the correct order of Holds, HoldFirsts,
HoldPatterns , Evaluate , Unevaluated etc... that make Mathematica
happy.
By the way, I already tried:
Plot[Evaluate[f[x,#]&/@{y1,y2,....,yn}],{x,a,b}]
but didn=B4t work.
I=B4ll give an specific example:
f[x_, y_] := NIntegrate[2^(s*x), {s, 0, y}]
Plot[Evaluate[f[x, #] & /@ {2, 3, 4, 5}], {x, 0.5, 1.5}]
Generates the 4 curves after giving errors like:
\"NIntegrate::\"inum\" \"Integrand 2^(s*x) is not numerical at s = 1. \"
So what I want to do is that the x of the Plotting evaluation enters
f[x,y] before f even sees the x and start freaking out.
Thanks in advance
Atte. Andres Guzman
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--
Bob Hanlon
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