Re: Problem with replacement rules
- To: mathgroup at smc.vnet.net
- Subject: [mg91886] Re: [mg91851] Problem with replacement rules
- From: Bob Hanlon <hanlonr at cox.net>
- Date: Thu, 11 Sep 2008 06:18:20 -0400 (EDT)
- Reply-to: hanlonr at cox.net
Clear[x]; x[y_] = x /. Solve[y == x/a + b, x][[1]] -a (b-y) x[2] -a (b-2) Bob Hanlon ---- Simula <simula at mit.edu> wrote: ============= Hello, I have a very simple question but I didn't find an answer in mathematica help. I use Solve[expression(x,y),x]. Then, x is obtained as a one-to-one function of y. I want to define the function x(y) using the output of Solve. How should I do? Thank you very much for your help. Best regards, Laurent -- Bob Hanlon