Re: Working modulo 2

• To: mathgroup at smc.vnet.net
• Subject: [mg92120] Re: Working modulo 2
• From: Peter Pein <petsie at dordos.net>
• Date: Sat, 20 Sep 2008 05:01:27 -0400 (EDT)
• References: <gavt0g\$g4u\$1@smc.vnet.net>

```me13013 schrieb:
> Howdy,
>
> How does one reduce a polynomial's coefficients modulo 2?  For
> example, I have a function that sums several polynomials, and
> currently produces a result like this:
>   7 + x + 4 y + 4 x y + 3 z + 2 x z + 4 y z + 4 x y z
> I want to reduce this to
>   1 + x + z
>
> I thought I might be able to do this by somehow coercing the terms
> into a list and then doing Sum[L[[i]],{i,1,Length[L]},Modulus->2], but
> no such luck.
>
> Any ideas?
>
> Thanks,
> Bob H
>

Hi Bob,

ReplaceAll is what you need:

7+x+4 y+4 x y+3 z+2 x z+4 y z+4 x y /.i_Integer:>Mod[i,2]
1+x+z

Peter

```

• Prev by Date: How to consider two fitting methods when using Findfit in Mathematica
• Next by Date: Re: Working modulo 2
• Previous by thread: Re: Working modulo 2
• Next by thread: Re: Working modulo 2