Re: help in constructing a binomial consequence
- To: mathgroup at smc.vnet.net
- Subject: [mg98265] Re: help in constructing a binomial consequence
- From: mark mcclure <mcmcclur at unca.edu>
- Date: Sun, 5 Apr 2009 06:31:31 -0400 (EDT)
- References: <gr4jm9$ac5$1@smc.vnet.net>
On Apr 3, 5:08 am, Galina <Galina.Pil... at gmail.com> wrote:
> I need to find an eigenvalues of the matrix M [N*N] where elements
> are of the type F[i]*F[j]. I need help to construct the elements F[i]
> which must be in the following order: F[1]=1, F[2]=x, F[3]=y, F[4]
> =x^2, F[5]=x*y, F[6]=y^2, F[7]=y*x^2, F[8]=x*y^2, F[9]=x^3 an=
d etc....
Your pattern seems a bit off. I'm guessing you mean:
1, x, y, x^2, x y, y^2, x^3, x^2 y, x y^2, y^3
In this case, you can define your F like so:
biRow[n_] := Table[x^(n - k)*y^k, {k, 0, n}];
Clear[F];
m = 0;
Do[F[++m] = binom,
{binom, Flatten[Table[biRow[n], {n, 0, 3}]]}];
Then, you can define your matrix via:
M = Table[F[i]*F[j], {i, 1, m}, {j, 1, m}];
I'm guessing these matrices all have rank 1.
Thus, you can find the only non-zero eigenvalue
via:
Eigenvalues[M] // Last
Mark McClure