Re: Contour Plots of Lists
- To: mathgroup at smc.vnet.net
- Subject: [mg98661] Re: Contour Plots of Lists
- From: dh <dh at metrohm.com>
- Date: Thu, 16 Apr 2009 04:10:29 -0400 (EDT)
- References: <grpilq$lu4$1@smc.vnet.net>
Hi,
there is ListContourPlot.
But why you do not want mathematica to choose the points, simply using
ContourPlot:
ContourPlot[Abs[F(x + I y)],{x,1,100},{y,1,100}]
Daniel
tsg.moore at googlemail.com wrote:
> I'm familiar with the straightforward and simple commands of
> Mathematica, but am a bit unsure of how to do this. I have a
> complicated function f(z) that must be integrated from a known point
> to a parameter, z = s. Call this F(s). Mathematica can do the integral
> provided I tell it how to do it on a case-by-case basis.
>
> I need a contour plot of F(s) (s is complex). So I would need to
> program something like this:
>
> Create 100x100 mesh in [x, y]
>
> For 1:100
> --For 1:100
> ----Calculate F(x + iy) using specific fashion
> --end
> end
>
> ContourPlot[x, y, Abs[F]]
>
> Is there a way to do ContourPlots on discrete meshes? (I guess they're
> called Lists in Mathematica)
>