       Re: Contour Plots of Lists

• To: mathgroup at smc.vnet.net
• Subject: [mg98661] Re: Contour Plots of Lists
• From: dh <dh at metrohm.com>
• Date: Thu, 16 Apr 2009 04:10:29 -0400 (EDT)
• References: <grpilq\$lu4\$1@smc.vnet.net>

```
Hi,

there is ListContourPlot.

But why you do not want mathematica to choose the points, simply using

ContourPlot:

ContourPlot[Abs[F(x + I y)],{x,1,100},{y,1,100}]

Daniel

> I'm familiar with the straightforward and simple commands of

> Mathematica, but am a bit unsure of how to do this. I have a

> complicated function f(z) that must be integrated from a known point

> to a parameter, z = s. Call this F(s). Mathematica can do the integral

> provided I tell it how to do it on a case-by-case basis.

>

> I need a contour plot of F(s) (s is complex). So I would need to

> program something like this:

>

> Create 100x100 mesh in [x, y]

>

> For 1:100

> --For 1:100

> ----Calculate F(x + iy) using specific fashion

> --end

> end

>

> ContourPlot[x, y, Abs[F]]

>

> Is there a way to do ContourPlots on discrete meshes? (I guess they're

> called Lists in Mathematica)

>

```

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