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Re: Contour Plots of Lists

  • To: mathgroup at smc.vnet.net
  • Subject: [mg98661] Re: Contour Plots of Lists
  • From: dh <dh at metrohm.com>
  • Date: Thu, 16 Apr 2009 04:10:29 -0400 (EDT)
  • References: <grpilq$lu4$1@smc.vnet.net>


Hi,

there is ListContourPlot.

But why you do not want mathematica to choose the points, simply using 

ContourPlot:

ContourPlot[Abs[F(x + I y)],{x,1,100},{y,1,100}]

Daniel



tsg.moore at googlemail.com wrote:

> I'm familiar with the straightforward and simple commands of

> Mathematica, but am a bit unsure of how to do this. I have a

> complicated function f(z) that must be integrated from a known point

> to a parameter, z = s. Call this F(s). Mathematica can do the integral

> provided I tell it how to do it on a case-by-case basis.

> 

> I need a contour plot of F(s) (s is complex). So I would need to

> program something like this:

> 

> Create 100x100 mesh in [x, y]

> 

> For 1:100

> --For 1:100

> ----Calculate F(x + iy) using specific fashion

> --end

> end

> 

> ContourPlot[x, y, Abs[F]]

> 

> Is there a way to do ContourPlots on discrete meshes? (I guess they're

> called Lists in Mathematica)

> 




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