Re: Contour Plots of Lists

*To*: mathgroup at smc.vnet.net*Subject*: [mg98661] Re: Contour Plots of Lists*From*: dh <dh at metrohm.com>*Date*: Thu, 16 Apr 2009 04:10:29 -0400 (EDT)*References*: <grpilq$lu4$1@smc.vnet.net>

Hi, there is ListContourPlot. But why you do not want mathematica to choose the points, simply using ContourPlot: ContourPlot[Abs[F(x + I y)],{x,1,100},{y,1,100}] Daniel tsg.moore at googlemail.com wrote: > I'm familiar with the straightforward and simple commands of > Mathematica, but am a bit unsure of how to do this. I have a > complicated function f(z) that must be integrated from a known point > to a parameter, z = s. Call this F(s). Mathematica can do the integral > provided I tell it how to do it on a case-by-case basis. > > I need a contour plot of F(s) (s is complex). So I would need to > program something like this: > > Create 100x100 mesh in [x, y] > > For 1:100 > --For 1:100 > ----Calculate F(x + iy) using specific fashion > --end > end > > ContourPlot[x, y, Abs[F]] > > Is there a way to do ContourPlots on discrete meshes? (I guess they're > called Lists in Mathematica) >